Math, asked by suchitra253saket, 9 months ago

Factorise 8a3+125b3-64c3+120 abc

Answers

Answered by manasiRani

0

Answer:

(2a+5b-4c) +(4a2+25b2-16c2+10ab-20bc-8ac)

Answered by thunderstorm49

4

Answer:

8a3+125b3-64c3+120abc

a3+b3+c3-3abc=(a+b+c) (a2+b2+c2-ab-bc-ca)

a=(2a)

b=(5b)

c=(-4c)

(2a+5b-4c) (4a2+25b2+16c2-10ab+20bc+8ca)

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