Question

factorise 8a³+√27b³.... plz help meeeeeeee

Answer 1

8acube+27cube
=(2a)cube+(3b)cube
By formula
a cube+b cube= (a+b)(a square+ab+b square)
So,
8acube+27cube
=(2a)cube+(3b)cube
=(2a+3b)((2a) square+2ax3b+(3b) square)
=(2a+3b)(4a^2+6ab+9b^2)

Answer 2

Heya

Here goes your answer

8a³+√27b³

(2a)³ + √(3b)³

a³+b³=(a+b)(a²-2ab+b²)

= (2a+√3b) (4a²-2(2a×√3b) + 3b)

= (2a+√3b) ( 4a²-4a√3b+3b)

The factors are (2a+√3b) and (4a²-4a√3b+3b)