Question

Factorise: 8a3 + b3 + 12a2b + 6ab2


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Answer 1

8a³-b³-12a²b+6ab²

=(2a-b)(4a²+2ab+b²)-6ab(2a-b)

=(2a-b)(4a²+2ab+b²-6ab)

=(2a-b)(4a²-4ab+b²)

=(2a-b){(2a)²-2×2a×b+(b)²}

=(2a-b)(2a-b)²

=(2a-b)(2a-b)(2a-b)

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