factorise 8a³+b³+12a²b+6ab²
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Answer:
Using Algebraic Formula :-
[a-b]³= a³-b³-3ab(a-b)
8a³-b³-12a²b+6ab²
= 8a³−b³−12a²b+6ab²
= (2a)³+(−b)³+3(2a)(−b)(2a−b)
=(2a−b)³=(2a−b)(2a−b)(2a−b)
Step-by-step explanation:
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