Math, asked by bilalmuhammedbilal12, 6 months ago

Factorise 8a³ - b³- 12a²b+6ab²

Answers

Answered by gunguun18

1

Answer:

The identity used is : x^3-y^3 - 3xy (x - y)

Step-by-step explanation:

8a^3 - b^3 - 12 a^2b + 6ab^2

sol: (2a^3) -b^3 - 6a^2b ( 2a - b )

= 8a^3 - b^3 - 12a^2b - 6ab^2

=( 2a-b ) ^3 = (2a-b) (2a-b) (2a-b).

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