Question

Factorise: 8a³- b³- 4ax + 2bx

Answer 1

$= > 8a^{3} - {b}^{3} - 4ax + 2bx \\ = > (2a - b)(4 {a}^{2} + 2ab + b^{2} ) - 2x(2a - b) \\ = > (2a - b)(4 {a}^{2} + 2ab + {b}^{2} - 2x)$

Hope it'll help you.....

Answer 2

Answer:

(2a - b) (4a² + b² + 2ab - 2x)

Step-by-step explanation:

= 8a³ - b³ - 4ax -2bx

= [(2a)³ - (b)³] - 2x(2a - b)

Since, (a - b)³ = (a-b) (a²+ b² + ab)

= (2a - b) (4a² + b² + 2ab) - 2x (2a - b)

Now, taking common (2a - b)

= (2a - b) (4a² + b² + 2ab - 2x)

HOPE IT HELPS YOU..!!!