Factorise: 8a3 - b3 +64c3 + 24 abc
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Answered by
2
Answer:
8a³ - b³ + 64c³ + 24abc = (2a - b + 4c)(4a² + b² + 16c² + 2ab + 4bc - 8ca)
Step-by-step explanation:
We know that a³ + b³ + c³ - 3abc = (a + b + c)(a² + b² + c² - ab - bc - ca)
8a³ - b³ + 64c³ + 24abc = (2a)³ + (-b)³ + (4c)³ - 3×2a×-b×4c
= (2a - b + 4c)(4a² + b² + 16c² + 2ab + 4bc - 8ca)
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Answered by
2
Answer:
8a³ - b³ + 64c³ + 24abc = (2a - b + 4c)(4a² + b² + 16c² + 2ab + 4bc - 8ca)
Step-by-step explanation:
We know that a³ + b³ + c³ - 3abc = (a + b + c)(a² + b² + c² - ab - bc - ca)
8a³ - b³ + 64c³ + 24abc = (2a)³ + (-b)³ + (4c)³ - 3×2a×(-b)×4c
= (2a - b + 4c)(4a² + b² + 16c² + 2ab + 4bc - 8ca)
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