Factorise 8a3-b3+64c3+24abc
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8a3-b3+64c3+24abc
We know that:
a3+b3+c3-3abc=(a+b+c)(a2+b2+c2-ab-bc-ca)
(2a-b+4c)(4a2+b2+16c2+2ab+4bc-8ca)
Answered by
0
your answer is wrong
you have to explain it s further too
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