Factorise 8b3-1 using identity
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8b 3 - 1
your answer is : 8
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8b³ - 1
(2b)³ - (1)³
(2b - 1) [(2b)² - 2b×1 + (1)²]
(2b - 1) (4b² - 2b + 1)
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