factorise 8p^3 +12/5p^2 + 6/25p + 1/125
niva787:
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Solution:
/* a³+3a²b+3ab²+b³ = (a+b)³ */
Now ,
8p³+(12/5)p²+(6/25)p+1/125
= (2p)³+3*(2p)²*(1/5)+3*(2p)*(1/5)²+(1/5)³
= (2p+1/5)³
= (2p+1/5)(2p+1/5)(2p+1/5)
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