factorise 8p^3-125q^3
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8p³ = (2p)³
125q³ = (5q)³
We know that,
(a³ - b³) = (a - b)(a² + ab + b²)
8p³ - 125q³ = (2p - 5q)[(2p)² + (2p)(5q) + (5q)²]
8p³ - 125q³ = (2p - 5q)(4p² + 10pq + 25q²)
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