Math, asked by khusi123456, 11 months ago

factorise: 8p³+12/5p²+6/25p+1/125







Answers

Answered by naveenrastogi
16

8p3 + 125p2 + 625p + 1125=8p3 + 1125 + 125p2 + 625p=2p3 + 153 + 32p215 + 32p152=2p + 153 as, a3+b3+3a2b+3ab2 = a+b3=2p + 152p + 152p + 15

Answered by kamlerkarprakash
12

8p³-12/5p²+6/25p-1/125=

(2p)³-3(2p)²(1/5)+3(2p)(1/5)²-(1/5)³

It is in the form of (a-b)³=a³-3a²b+3ab²-b³

Here a=2p,b=1/5

(2p)³-3(2p)²(1/5)+3(2p)(1/5)²-(1/5)³=(2p-1/5)³

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