Math, asked by 9790238276hello, 5 months ago


Factorise 8p3 12 p2q + 6Pq2-q 3

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Answered by Anonymous
3

We are given, 

8p3−q3−12p2q+6pq2

=(2p)3−(q)3−6pq(2p−q)

=(2p)3−(q)3−3(2p)(q)(2p−q)

Let a=2p= & b=q

So, 

(a)3−(b)3−3ab(a−b)

=(a−b)3

So, 

(2p)3−(q)3−3(2p)(q)(2p−q)=(2p−q)3

So, 

8p3−q3−12p2q+6pa2

=(2p−q)(2p−q)(2p−q)

Hope it helps you.........

Answered by shaikhaafreen980
0

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