Factorise 8p3 12 p2q + 6Pq2-q 3
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We are given,
8p3−q3−12p2q+6pq2
=(2p)3−(q)3−6pq(2p−q)
=(2p)3−(q)3−3(2p)(q)(2p−q)
Let a=2p= & b=q
So,
(a)3−(b)3−3ab(a−b)
=(a−b)3
So,
(2p)3−(q)3−3(2p)(q)(2p−q)=(2p−q)3
So,
8p3−q3−12p2q+6pa2
=(2p−q)(2p−q)(2p−q)
Hope it helps you.........
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