factorise 8p3-12p2q+6pq-q3
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Sushantmultonia:
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We are given,
8p
3
−q
3
−12p
2
q+6pq
2
=(2p)
3
−(q)
3
−6pq(2p−q)
=(2p)
3
−(q)
3
−3(2p)(q)(2p−q)
Let a=2p= & b=q
So,
(a)
3
−(b)
3
−3ab(a−b)
=(a−b)
3
So,
(2p)
3
−(q)
3
−3(2p)(q)(2p−q)=(2p−q)
3
So,
8p
3
−q
3
−12p
2
q+6pa
2
=(2p−q)(2p−q)(2p−q)
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