Question

Factorise 8p³-2p by using suitable identity​

Answer 1

heya....

$2p(4p {}^{2} - 1)$

Using

$x {}^{2} - y {}^{2} = (x + y)(x - y)$

$2p(2p) {}^{2} - 1 {}^{2}$

$2p(2p - 1)(2p + 1)$

Hope it helps

Answer 2

$2p(4p^{2} - 1 > \\ 2p < (2p)^{2} - (1)^{2} > \\ 2p(2p + 1)(2p - 1)$