Question

factorise:8x^2+21x-9​

Answer 1

Answer:

8x²+21x-9

8x²+24x-3x-9

8x(x+3)-3(x+3)

(8x-3)(x+3)

Therefore factors are (8x-3)(x+3)

And zeroes are 8x-3 = 0

8x = 3

X = 3/8 and other zero is x+3 = 0

X = - 3

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