Factorise 8x^3+ 125.
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Rewrite 8x3 8 x 3 as (2x)3 ( 2 x ) 3 . Rewrite 125 as 53 . Since both terms are perfect cubes, factor using the difference of cubes formula, a3−b3=(a−b)(a2+ab+b2) a 3 - b 3 = ( a - b ) ( a 2 + a b + b 2 ) where a=2x a = 2 x and b=5 .
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