Question

Factorise 8x^3-27y^3

Answer 1

8x^3 - 27y^3 = (2x)^3 - (3y)^3

= ( 2x - 3y) [(2x)^2 + (3y)^2 + (2x) (3y) ]

= ( 2x - 3y) ( 4x^2 + 9y^2 + 6xy )

identity used: a^3 + B^3 = (a-b) (a^2 + b^2 + ab)

hope this helps you

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