factorise 8x^3+27y^3
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8x³+27y³
=>(2x)³+(3y)³
We know that a³+b³=(a+b)(a²+b²-ab)
=>(2x+3y)[(2x)²+(3y)²-2x×3y]
=>(2x+3y)(4x²+9y²-6xy)
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