Math, asked by pparnami77, 9 months ago

Factorise:8x^3-(2x-3y)^3

Answers

Answered by rajkumarh75
2

Answer:

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Answered by kaspaprathyusha
6

Answer:

Given, 8x^3 - (2x - y) ^3  

= (2x) ^3 - (2x - y) ^3  

Using the formula:

a^3 - b^3= (a - b)(a^2 + ab + b^2) -------- eq.(1)  

Putting the value of a = 2x, b = (2x – y) in the above formula; we get  

= (2x – (2x+y)) {(2x) ^2 - 2x*(2x - y) + (2x - y) ^2}  

= y {(4x^2 - 4x^2 + 2xy + 4x^2 - 4xy + y^2)}  

= y (4x^2 - 2xy + y^2)

Therefore, factorized form of the given problem is y (4x^2 - 2xy + y^2).

Step-by-step explanation:

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