factorise 8x^3-(2x-y)^3
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Answer:
y ( 12x² – 6xy + y² )
Step-by-step explanation:
8x³ – ( 2x – y )³
= (2x)³ – ( 2x – y )³
=( 2x – 2x + y ) { (2x)² + 2x*(2x–y) + (2x–y)²}
= y { 4x² + 4x² – 2xy + 4x² – 4xy + y² }
= y ( 12x² – 6xy + y² )
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