Question

Factorise 8x^3+3root 3 y^3

Answer 1

Step-by-step explanation:

8x³+3√3y³

→(2x)³+(√3y)³

→(2x+√3y)(4x²-2√3xy+3y²)

problem is solved by using the formula

a3 + b3 = (a + b) (a2 - ab + b2 ).

Here is ur solution...

Hope so it will help you dear ☺️

Answer 2

Answer:

8x^3=(2x-y)^3

=(2x)^3-(2x-y)^3

using the formula

8^3-b^3=(a-b)(a^2+ab+b^2)

put the value of a 2x,b=(2x-y)

=(2x-(2x+y) {(2x)^2-2x(2x-y)+(2x-y)^2)

=y(4x^2-4x^2+2xy+4x^2-4xy+y^2)

= y(4x^2-2xy+y^ 2)

The Factorised from the given is y (4 x^2-2xy+ y^2) STEP_by_STEP EXPLAN ( PLEASE MAKE ME BRANLIST)