factorise 8x^3-4x^2-18x+9
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Heya ✋
Let see your answer !!!!!
8x^3 - 4x^2 - 18x + 9
= 4x^2(2x - 1) - 9(2x - 1)
= (2x - 1) (4x^2 - 9)
= (2x - 1) [(2x)^2 - (3)^2]
= (2x - 1) (2x + 3) (2x - 3)
Thanks :)))))
Let see your answer !!!!!
8x^3 - 4x^2 - 18x + 9
= 4x^2(2x - 1) - 9(2x - 1)
= (2x - 1) (4x^2 - 9)
= (2x - 1) [(2x)^2 - (3)^2]
= (2x - 1) (2x + 3) (2x - 3)
Thanks :)))))
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