Question

factorise 8x^4 + 14x^2 - 4​

Answer 1

Step-by-step explanation:

8x^4 + 14x^2 - 4

=2(4x^4+7x^2-2)

=2(4x^4+8x^2-x^2-2)

=2((4x^2(x^2+2)-1(x^2+2))

=2(4x^2-1)(x^2+2)

=2((2x)^2-1)(x^2+2)

=2(2x-1)(2x+1)(x^2+2)