Question

Factorise: 8x cube +y cube +z cube - 6XYZ

Answer 1

Answer:

  8x³ +y³ + z³ - 6xyz

= (2x)³ +y³ + z³ - 3(2x)(y)(z)

Now using identity : $a^{3}\ +\ b^{3}\ +\ c^{3}\ -\ 3abc\ =\ (a+b+c)(a^{2}\ +\ b^{2}\ +\ c^{2}\ -\ ab-bc-ca)$

⇒ (2x+y+z)[(2x)² + y² + c² - 2xy - yz - 2xz]

= (2x+y+z)(4x² + y² + c² - 2xy - yz - 2xz)

$Here\ is\ your\ answer\ buddy :)$

Step-by-step explanation:

Hope it helps you