Question

. FACTORISE
(8x² - 4)
AND FIND ZEROS .​

Answer 1

Answer:

$(8x) ^{2} - (4) \\ =( 2 \sqrt{2} ) { }^{2} - 2 \\ = 2 \sqrt{2 } - 2 \: and \: 2 \sqrt{2} + 2 \\ = when \\ = 2 \sqrt{2} - 2 = 0 \\ = 2 \sqrt{2} = 2 \\ \\ when \\ = 2 \sqrt{2} + 2 = 0 \\ = 2 \sqrt{2} = - 2$