Factorise 8x³/27+y³/125
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Answer:
Step-by-step explanation:
Using Identity (a+b)³ = a³+ b³ + 3ab(a + b)
⇒ a³+ b³ = (a+b)³ - 3ab(a + b)
⇒ a³+ b³ = (a+b)((a+b)² - 3ab)
⇒ a³+ b³ = (a+b)(a²+b² - ab)
8x³/27+y³/125
= (2x/3)³ + (y/5)³
= (2x/3 + y/5)(4x²/9 + y²/25 - 2xy/15)
=
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ek sec ke liye gussa aayega na?
Toh fir!
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