Question

Factorise :- 8x³ - (2x - 3y)³​

Answer 1

Answer:

${8x}^{3} - ( {2x - 3y)}^{3}$

$= {8x}^{3} - ( {8x}^{3} - {27y}^{3} + 12 {y}^{2} x - {12x}^{2} y = 0$

$= {27x}^{3} - 12 {y}^{2}x + 12 {x}^{2}y$

Answer 2

Answer:

Answer:

{8x}^{3} - ( {2x - 3y)}^{3}8x

3

−(2x−3y)

3

= {8x}^{3} - ( {8x}^{3} - {27y}^{3} + 12 {y}^{2} x - {12x}^{2} y = 0=8x

3

−(8x

3

−27y

3

+12y

2

x−12x

2

y=0

= {27x}^{3} - 12 {y}^{2}x + 12 {x}^{2}y=27x

3

−12y

2

x+12x

2

y