Question

Factorise: 8x³-(2x-y)³

Answer 1

hye

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we have to  Factorise: 8x³-(2x-y)³



=>8x³ - (2x - y)³


=> 8x³ - [(2x)³ - y³ - 3(2x)(y)(2x - y)]

=> 8x³ - [8x³ - y³ - 6xy(2x - y)]


= >8x³ - 8x³ + y³ + 6xy(2x - y)


=>y³ + 12x²y - 6xy²


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hope it helps u

Answer 2

Hey friend, Harish here.

Here is your answer:

Given ,

An expression 8x³ - (2x - y)³ which must be factorized.

Solution:

We know that, 

(a³ - b³) = ( a - b ) ( a² + ab + b² )

⇒ 8x³ - (2x - y)³ = (2x)³ - (2x - y)³

⇒ (2x - 2x + y) ( (2x)² + (2x)(2x-y) + (2x - y)² )

⇒ (y)( 4x² + 4x² - 2xy + 4x² + y² - 4xy)

⇒ (y) (12x²  + y² - 6xy)
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Hope my answer is helpful to you.