Question

Factorise

8x³-y³-12x²y+6xy²

Answer 1

$\textbf{Hey mate! }$

$\textbf{Solution:}$

We will use the following identity,

➠ x³ - y³ - 3x²y + 3xy² = (x - y)³

Given,

➠ 8x³ - y³ - 12x²y + 6xy²

⇒ 2x³ - y³ - 3(2x)²(y) + 3(2x)(y)²

⇒(2x - y)³

⇒(2x - y)(2x - y)(2x - y)


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Answer 2

Answer:

$\Large{\underline{\underline{\bf{Solution:-}}}}$

$8 {x}^{3} - {y}^{3} - 12 {x}^{2} y + 6x {y}^{2} \\ \\ using \: identity \: { (x - y)}^{3} = {x}^{3} - {y}^{3 } - 3 {x}^{2} y + 3x {y}^{2} \\ \\ now \\ \\ = 2 {x}^{3} - {y}^{3} - 3 {(2x)}^{2} y + 3(2x) {y}^{2} \\ \\ = {(2x - y)}^{3} \\ \\ = (2x - y)(2x - y)(2x - y)$

$\huge\mathfrak\red{thanks}$