Question

Factorise :- 8xcube-64​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

The factorisation of 8$x^3$ - 64 = $(2x-4)(4x^{2}+8x+16)$.  

Step-by-step explanation:

We have,

8$x^3$ - 64

To find, the factorisation of 8$x^3$ - 64 = ?

∴ 8$x^3$ - 64

= $(2x)^{3}-4^{3}$

Using the algebraic identity,

$a^{3}-b^{3}=(a-b)(a^{2}+ab+b^{2})$

= $(2x-4)((2x)^{2}+(2x)(4)+4^{2})$

= $(2x-4)(4x^{2}+8x+16)$    

∴ The factorisation of 8$x^3$ - 64 = $(2x-4)(4x^{2}+8x+16)$  

Thus, the factorisation of 8$x^3$ - 64 is equal to $(2x-4)(4x^{2}+8x+16)$.