factorise - 8xcube +ycube+27zcube-3xyz
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Step-by-step explanation:
8x³ +y³+27z³-3xyz
here we can use Identity:
x³+y³+z³-3xyz= (x+y+z)(x²+y²+z²-xy-yz-zx)
(2x)³+y³+(3z)³-3xyz= (2x+y+3z)(4x²+y²+9z²-2xy-3yz-6xz)
so, the factorized form will be :
(2x+y+3z)(4x²+y²+9z²-2xy-3yz-6xz)
hope it will help u
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