Question

factorise
8y^3+125z^3​

Answer 1

First make a complete cube.

= (2y)^3 + (5z)^3

USING THE IDENTITY,

a^3+b^3 = (a+b) (a^2-ab+b^2)

(2y)^3 + (5z)^3 = (2y+5z) (4y^2-10yz+25z^2)

Thus, the factorisation of 8y^3+125z^3 is (2y+5z) (4y^2-10yz+25z^2)

Answer 2

$\huge\mathfrak\blue{ANSWER}$

GIVEN,

$factorise->>>8y^3+125z^3$

Now,

$\huge\mathfrak\blue{First\:simplify\:it}$

$2y^3+5z^3$

$\mathtt\{Using\:a^3+b^3=(a+b)(a^2-ab+b^2)$

$(2y+5) (4y^2-10yz+25z^2)$

$\mathcal{Some\:of\:the\:identities}$

$(a+b)^2=a^2+2ab+b^2$

$(a-b)^2=a^2-2ab+b^2$

Thank You!