Math, asked by kamal181, 1 year ago

factorise 8y cube - 125x cube

Answers

Answered by Yash061
42
Hey Mate! Here's ur answer.
Factorise 8y^3 - 125x^3
=> (2y)^3 - (5x)^3
=> (2y - 5x){(2y)^2+2y.5x+(5x)^2}
=> (2y - 5x){4y^2+10xy+25x^2}

I Hope It Helps....☺️

Anonymous: u r wrong bro
kamal181: why
Anonymous: this wrong method to do factorisation
Anonymous: see my ans is ryt
kamal181: kk
Anonymous: ☺️
Answered by pulakmath007
4

 \sf 8 {y}^{3}  - 125 {x}^{3}  = (2y - 5x)(4 {y}^{2}  + 10xy + 25 {x}^{2} )

Given :

The expression 8y³ - 125x³

To find :

To factorise the expression

Solution :

Step 1 of 2 :

Write down the given expression

The given expression is

8y³ - 125x³

Step 2 of 2 :

Factorise the expression

 \sf 8 {y}^{3}  - 125 {x}^{3}

 \sf  =  {(2y)}^{3}  -  {(5x)}^{3}

 \sf  =(2y - 5x) \{  \:  {(2y)}^{2}   + 2y.5x +   {(5x)}^{2} \:   \}

 \sf  = (2y - 5x)(4 {y}^{2}  + 10xy + 25 {x}^{2} )

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