Question

factorise 9(3x+1)² - 2(x-1)² please answer fast​

Answer 1

9 ( 3x + 1 ) ² - 2 ( x - 1) ²

= 9 [ (3x)² + 2(3x)(1) + (1)² ] - 2 [ (x)² + 2(x)(-1) + ( -1) ² ]

= 9 [ 9x² + 6x + 1 ] - 2 [ x² - 2x + 1 ]

= 81x² + 54x + 9 - 2x² + 4x - 2

= 81x² - 2x² + 54x + 4 x + 9 - 2

= 79x² + 58x + 7

I hope this will be help you

Answer 2

Answer:

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Step-by-step explanation:

$9(3x+1)^2 - 2(x-1)^2\\\\Using\:\:formula\:\: (a+b)^2 = a^2+2ab+b^2 \:\:\:and\:\:(a-b)^2=a^2-2ab+b^2, we\:\:get:-\\\\9[(3x)^2 +(2\times3x\times2)+(1)^2 ] - 2 [(x)^2 - 2 \times x \times1+(1)^2]\\\\9 (9x^2 + 6x + 1) - 2 (x^2 - 2x+1)\\\\81x^2+54x+9-2x^2+4x-2\\\\81 x^2 - 2x^2 +54x + 4x + 9 - 2\\\\79x^2 + 58x + 7$