Question

Factorise: 9(3x + 1)2 – 4 (x – 1)^2

Answer 1

Answer:

77x^2+46x+5

Step-by-step explanation:

9x(9x^2+6x+1)-4(x^2+2x+1)

=81x^2+54x+9-4x^2-8x-4

=77x^2+46x+5

Answer 2

Step-by-step explanation:

9(3x + 1)2 – 4 (x – 1)^2

$9(3x + 1)2 – 4 (x – 1)^2 = 0 \\ 54x + 18 - 4( {x}^{2} - 2x + 1) = 0 \\ 54x+18−4 {x}^{2} + 8x - 4 = 0 \\ 62x + 14 - 4 {x}^{2} = 0 \\ 4 {x}^{2} - 62x - 14 = 0 \\ 2 {x}^{2} - 31x - 7 = 0 \\ d = b {}^{2} - 4ac \\ b = - 31 \\ c - 7 \\ a = 2 \\ d = 1017 \\ \alpha = \frac{ - b \frac{ + }{} \sqrt{d} }{2a}$