Question

Factorise 9(3x +2)^2 - 4(2x-1)^2

Answer 1

Step-by-step explanation:

$9 {(3x + 2)}^{2} - 4 {(2x - 1)}^{2}$

${3}^{2} {(3x + 2)}^{2} - {2}^{2} {(2x - 1)}^{2}$

${(3(3x + 2))}^{2} - {(2(2x - 1))}^{2}$

${(9x + 6)}^{2} - {(4x - 2)}^{2}$

$(9x + 6 + 4x - 2)(9x + 6 - 4x + 2)$

$(13x + 4)(5x + 8)$