factorise 9(3x+2)^2-8(x-2y)-16
Answers
Answered by
0
Answer:
Correct option is C)
15(x−2y)
2
−8(x−2y)−16
let x-2y=p then,
15(x−2y)
2
−8(x−2y)−16=15p
2
−8p−16
=15p
2
+12p−20p−16
=3p(5p+4)−4(5p+4)
=(5p+4)(3p−4)
Substituting p=x-2y we get
=[5(x−2y)+4][3(x−2y)−4]
=(5x−10y+4)(3x−6y−4)
Similar questions