Question

Factorise 9-3y+y^2 .Please send I will mark as brainliest

Answer 1

$y {}^{2} - 3y + 9$

Comparing it with

$ax {}^{2} + bx + c = 0$

we get a=1

b=-3

c=9

$using \: \\ x = - b \binom{ + }{ - } \sqrt{b {}^{2} - 4ac } \div 2a$

substituting values of a b and c

$y = - ( - 3) + - \sqrt{( - 3) {}^{2} - 4(1)(9) } \div 2a$

$y = 3 + - \sqrt{9 - 36} \div 2(1)$

$3 + - \sqrt{27} \div 2(1)$

taking

$\sqrt{27} = 5(approx)$

we get

$y = 3 + - 5 \div 2$

$y = 3 + 5 \div 2 = 8 \div 2 \\ y = 3 - 5 \div 2 = - 2 \div 2$

we get y=4 or -1(Approximately)

Answer 2

there are no factors

but y^2-3y+9

=y(y-3)+9