Question

Factorise:
9(6 + 2a)^ - 4a^​

Answer 1

Answer:

9(b + 2a)^2-4a^2 = (3b+4a)(3b+8a)

Step-by-step explanation:

9(b + 2a)^2-4a^2 = (3^2)(b+2a)^2 - (2^2)(a^2)

= [3(b+2a)]^2-(2a)^2

= [3(b+2a)-2a][3(b+2a)+2a]

= [3b+6a-2a][3b+6a+2a]

= (3b+4a)(3b+8a)

Answer 2

Step-by-step explanation:

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