Question

factorise 9(a-2b)^2+6(2b-a)^2
donot write unnessesarily​

Answer 1

$9( {a - 2b)}^{2} + 6( {2b - a)}^{2} = 0 \\ \\ 9( {a}^{2} - 4ab + 4 {b}^{2} ) + 6(4 {b}^{2} - 4ab + { {a}^{2} ) = 0} \\ \\ 9 {a}^{2} - 36ab + 36 {b}^{2} + 24 {b}^{2} - 24ab + 6 {a}^{2} = 0 \\ \\ 15 {a}^{2} - 60ab + 60 {b}^{2} = 0 \\ \\ {a}^{2} - 4ab + 4 {b}^{2} = 0 \\ .......(dividing \: by \: 15) \\ \\ {a}^{2} - 2ab - 2ab + 4 {b}^{2} = 0 \\ \\ a(a - 2b) - 2b(a - 2b) = 0 \\ \\ (a - 2b)(a - 2b) = 0 \\ \\ a = 2b.......a = 2b$

hope it helps......

mark it as brainliest....✔✔