Question

factorise 9(a+b-c)² - 24(a+b-c) + 16​

Answer 1

Step-by-step explanation:

Let a+b-c=x

therefore equation is

$9 {x}^{2} - 24x + 16$

$9 {x}^{2} - 12x - 12x + 16$

$3x(3x - 4) - 4(3x - 4)$

${(3x - 4)}^{2}$

${(3(a + b - c) - 4)}^{2}$

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