Question

factorise 9(a+b+c)²-9​

Answer 1

Answer:

answer is (3a + 3b + 3c - 3)(3a + 3b+ 3c + 3)

Step-by-step explanation:

9(a+b+c)SQ - 9 = (3(a+b+c))sq- 3sq =(3a + 3b + 3c +3)(3a + 3b + 3c -3)[a square- b square = (a+b)(a-b)]

Answer 2

Step-by-step explanation:

Your answer is:

9a²+18ab+18ac+9b²+18bc+9c²-9

Hope It Helps You.