Math, asked by seemapandeyak, 3 months ago

factorise 9-a⁶+2a³b³-b⁶.​

Answers

Answered by muskaansubba13
2

I hope this will be helpful .

Attachments:
Answered by pulakmath007
4

SOLUTION

TO FACTORISE

 \sf{9 -  {a}^{6}  + 2 {a}^{3}  {b}^{3} -  {b}^{6}  }

FORMULA TO BE IMPLEMENTED

 \sf{ {a}^{2}  -  {b}^{2}  = (a + b)(a - b) }

EVALUATION

 \sf{9 -  {a}^{6}  + 2 {a}^{3}  {b}^{3} -  {b}^{6}  }

 \sf{ = 9 - ( {a}^{6}   -  2 {a}^{3}  {b}^{3}  +  {b}^{6})  }

 \sf{ = 9 -  \bigg[  { ({a}^{3} )}^{2}   -  2. {a}^{3} . {b}^{3}  +  { ({b}^{3} )}^{2} \bigg] }

 \sf{ =  {(3)}^{2}  -  \bigg[  { ({a}^{3} -  {b}^{3}  )}^{2} \bigg] }

 \sf{ =  (3 +{a}^{3} -  {b}^{3}  )(3 -{a}^{3}  +   {b}^{3}   ) }

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