Question

factorise 9 into 2 a minus b whole square minus 4 into 2 a minus b minus 13​

Answer 1

Factorise:

Step-by-step explanation:

$\ Given \ value:\\\\9(2a - b)^2-4(2a-b)-13\\\\ \ Solution:\\\\9(2a - b)^2-4(2a-b)-13\\\\ \rightarrow (2a-b) = x\\\\ \rightarrow 9x^2-4x-13 \\\\ \rightarrow 9x^2-(13-9)x-13 \\\\ \rightarrow 9x^2-13x+9x-13 \\\\ \rightarrow x(9x-13)+1(9x-13) \\\\ \rightarrow (9x-13)(x+1)\\\\\ put \ the \ value \ of \ x \\\\(9(2a-b)-13) ((2a-b)+1)\\\\\ factors: \ \ \ (18a-9b-13) (2a-b+1)$

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• Factorise: https://brainly.in/question/4565571

Answer 2

Step-by-step explanation:

1. To factorise the polynomial, 9(2a - b)2 - 4(2a - b) -13, consider x = (2a - b)

• So, 9(2a - b)2 - 4(2a - b) -13

= 9x2 - 4x -13

= 9x2 + 9x - 13x -13

= 9x(x + 1) - 13(x + 1)  

= (x + 1) (9x - 13)

= [(2a - b) + 1] [9(2a - b) - 13]                     [Since x = (2a - b)]

= (2a - b + 1) (18a - 9b - 13)