Question

Factorise : 9(x-2y)2 - 4(x-2y)- 13

Answer 1

Answer:

$\red { 9(x-2y)^{2}-4(x-2y)-13}$

$\green {= (x-2y+1)(9x-18y-13)}$

Step-by-step explanation:

Given expression 9(x-2y)² - 4(x-2y) - 13

/* Splitting the middle term, we get

= 9(x-2y)^{2} + 9(x-2y) - 13(x-2y) - 13

= 9(x-2y)[x-2y + 1] - 13(x-2y+1)

= (x-2y+1)[9(x-2y) - 13]

= (x-2y+1)(9x-18y-13)

Therefore.,

$\red { 9(x-2y)^{2}-4(x-2y)-13}$

$\green {= (x-2y+1)(9x-18y-13)}$

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Answer 2

refer to the attached file

thanks for the question