Question

factorise 9 x cube + 3 x square - 5 x minus one​

Answer 1

Answer:

check your question again, according to me this should be the equation : $9x^{3}$ - $3x^{2}$ - 5x -1

Step-by-step explanation:

$9x^{3}$ - $3x^{2}$ - 5x -1

From hit and trial method 1 is a factor

then (9x^3-3x^2-5x-1)/(x-1) = 9x^2 +6x +1

so factorizing 9x^2+6x+1 = 0

(3x + 1)^2 = 0

x = -1/3

so after factorizing 9x^3-3x^2-5x-1 =

(x-1)(3x+1)^2

So it's roots are 1,-1/3,-1/3

let me know if its right, if not then report this answer will try to do it again