Question

factorise 9 x square - 12 x + 3

Answer 1

9x^2-12x+3=0
3(3x^2-4x+1)=0
3x^2-4x+1=0
3x^2-(3+1)x+1=0
3x^2-3x-1x+1=0
3x(x-1)-1(x-1)=0
(x-1) (3x-1)=0
x=1
3x=1
x=1/3

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I hope you understand :-)

Answer 2

Heya,

Ur answer is here.

Given :- 9x² - 12x + 3 = 0.

As we see that each term has 3 as common factor, So let us divide the both sides by 3 to make it more simple.

So, 3x² - 4x + 1 = 0.

Now, we have to find two numbers A and B such that A + B = -4 and A X B = 3.
As, 3 = 1 X 3.
So, We can see that the two numbers A and B are -1 and -3 respectively.
Bcoz, -3 X -1 = 3 and - 3 + (-1) = -4.

3x² - 4x + 1 = 0
3x² - 3x - x + 1 = 0
3x (x -1) -1(x-1) = 0
(3x-1)(x-1) = 0

Hence, factorised. 
We can obtain zeroes from here too
As, (3x-1)(x-1) = 0(3x-1) = 0                or  (x-1) = 0

 x = 1/3                    or x = 1.
Hence, zeroes of given polynomial are 1/3 and 1.

Hope it helps...