factorise 9 x square - 48 x + 64
Answers
Answered by
20
Hi !!
This is your answer.
9x² - 48x + 64 = 0
let us find two numbers a and b such that a + b = -48 and a X b = 64 X 9.
Hence, a = -24 and b = -24 as
a X b = 64X9 = -24 X -24
and . a + b = -24 -24 = -48.
So, 9x² - 48x + 64 = 0
9x² - 24x -24x + 64 = 0
3x (3x - 8) - 8 (3x - 8) = 0
(3x - 8) (3x- 8) = 0.
By comparing with 0,
3x - 8 = 0
x = 8/3 and x = 8/3.
Hence, the zeroes of the polynomial are 8/3 and 8/3.
Hope it helps
This is your answer.
9x² - 48x + 64 = 0
let us find two numbers a and b such that a + b = -48 and a X b = 64 X 9.
Hence, a = -24 and b = -24 as
a X b = 64X9 = -24 X -24
and . a + b = -24 -24 = -48.
So, 9x² - 48x + 64 = 0
9x² - 24x -24x + 64 = 0
3x (3x - 8) - 8 (3x - 8) = 0
(3x - 8) (3x- 8) = 0.
By comparing with 0,
3x - 8 = 0
x = 8/3 and x = 8/3.
Hence, the zeroes of the polynomial are 8/3 and 8/3.
Hope it helps
Answered by
15
Heya !
Given equation,
9x² - 48x + 64 = 0
-> 9x² - 24x -24x + 64 = 0
-> 3x (3x - 8) - 8 (3x - 8) = 0
-> (3x - 8) (3x- 8) = 0
-> 3x - 8 = 0 or 3x - 8 = 0.
-> x =8/3 or x = 8/3.
Hence, the two zeroes of the polynomial are 8/3 and 8/3.
---------------------------------------------------------------------------
Given equation,
9x² - 48x + 64 = 0
-> 9x² - 24x -24x + 64 = 0
-> 3x (3x - 8) - 8 (3x - 8) = 0
-> (3x - 8) (3x- 8) = 0
-> 3x - 8 = 0 or 3x - 8 = 0.
-> x =8/3 or x = 8/3.
Hence, the two zeroes of the polynomial are 8/3 and 8/3.
---------------------------------------------------------------------------
Similar questions