factorise 9 x square Y - 24 x y square + 16 y cube
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Answered by
10
Answer:
9x²y - 24xy² + 16y³ = y(3x - 4y)²
Step-by-step explanation:
Factorise 9 x square Y - 24 x y square + 16 y cube
9x²y - 24xy² + 16y³
Taking y common
= y (9x² - 24xy + 16y²)
= y( 9x² - 12xy - 12xy + 16y²)
= y( 3x(3x - 4y) - 4y(3x - 4y))
= y (3x -4y)(3x - 4y)
= y(3x - 4y)²
9x²y - 24xy² + 16y³ = y(3x - 4y)²
Answered by
0
Answer:
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Step-by-step explanation:
=>y(9x²-24xy²+16y²)
=>y(9x²-24xy²+16y²)=>y[3x(3x-4y)-4y(3x-4y)]
=>y(9x²-24xy²+16y²)=>y[3x(3x-4y)-4y(3x-4y)]=>y(3x-4y)(3x-4y)
=>y(9x²-24xy²+16y²)=>y[3x(3x-4y)-4y(3x-4y)]=>y(3x-4y)(3x-4y)=>y(3x-4y)²
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